CWEA Maintenance Technologist Practice Test

To determine the power dissipated in the resistor, you can use the formula for electrical power, which is given by \( P = \frac{V^2}{R} \), where \( P \) is the power in watts, \( V \) is the voltage in volts, and \( R \) is the resistance in ohms. In this scenario, you are given the voltage \( V = 17.32 \) volts and the resistance \( R = 50 \) ohms. Plugging in these values into the formula: 1. First, square the voltage: \[ V^2 = (17.32)^2 = 300.8624 \] 2. Next, divide this value by the resistance: \[ P = \frac{300.8624}{50} = 6.017248 \] Rounding this to a suitable degree of precision gives the power dissipated in the resistor as approximately 6.0 watts. Therefore, the correct answer is 6.0 watts. This shows how power dissipation in a resistive component can be calculated directly from voltage and resistance, highlighting the fundamental relationship between these electrical parameters.